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Beryllium tellurate has the molecular formula of BeTeO4 and the molecular weight of 200.61 grams per mole. Its solubility is 6.72 g/100 ml at 20°C. It can be prepared by the solid-state reaction of TeO3 and BeO:
BeO+ TeO3 ? BeTeO4
This is the tetragonal composition. It can also be formed in the same manner by solid-state reaction of telluric acid:
BeO(solid)+ H2TeO4(solid) ? BeTeO4(solid)+H2O(gas)
Telluric acid is soluble in water and produces Te(OH)4O^2- anions in solutions. If beryllium chloride is added, the product is a tetrahydrate:
BeCl2(aq)+H2Te(OH)4(aq) ? {Be(OH)}2Te(OH)4

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where the tellurate complex changes from an octahedral to a tetrahedral configuration. Although the chemistry of beryllium tellurate was studied earlier, it has received no attention in the current literature. According to Topsoe (1872), beryllium tellurate crystallizes in the rhombohedral system with a ratio of lattice parameters a:b:c = 1:0.9602:0.9027. More recently, this compound has been said to be cubic and have a structure very similar to spinel, MgAl2O4. A compound having the molecular formula of Be4TeO7 is said to be isomorphous to spinel as well.

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